Cartesian equation:
x3 + y3 = 3axy
or parametrically:
x = 3at/(1 + t3), y = 3at2/(1 + t3)
Click below to see one of the Associated curves.
The problem to determine the tangent to the curve was proposed to Roberval who also wrongly believed the curve had the form of a jasmine flower. His name of fleur de jasminwas later changed.
The curve is sometimes known as the noeud de ruban.
The folium has an asymptote x + y + a = 0.
The equation of the tangent at the point with t = p is
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