Let *ABC* be any triangle. Trisect each side, so that *AB* has *C*_{1} and *C*_{2} as the two trisection points and similarly for the other two sides. Draw the lines *AA*_{1}, *AA*_{2}, *BB*_{1}, *BB*_{2}, *CC*_{1}, *CC*_{2}. These lines define an hexagonal region in the middle of triangle *ABC*. Then the area of the hexagonal region is ^{1}/_{10} the area of *ABC*.