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Q: What is (a-b plus c)2?

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If, as is normal, ab represents a times b, etc then ab + ab + cc = 2ab + c2 which is generally not the same as abc.

12c

(a+b+c) 2=a2+ab+ac+ba+b2+bc+ca+cb+c2a2+b2+c2+2ab+2bc+2ca [ ANSWER!]

C2+6c-9

C = sqrt(C2) C2 = A2 + B2 - 2 A B cos(AB)

What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)

a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c

No , a mom with o plus will have a o plus child only. If the child is ab plus then mom will also be ab plus

yes because ab plus bc is ac

a2

yeah the child can be A+, B+ or AB+

Commutativity.

l a2 b2 is c2!!Its completely norma

then the baby will be O plus, or AB plus , I think .

no they cant. they can only give a birth to another ab plus, or another b plus and an a plus... coz th possible genotype for ab is only AB. th possible genotype for b is BB or OB.

2ab

H2s+c2=

C2h2+ 2h2 = c2h6

associative property

C2+

a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z

Yes.

AB pos or AB neg

Can a woman who has B+ blood and a man who has AB- blood have a child with AB+ blood?

x2+bx+ax+ab = x2+ax+bx+ab = x(x+a)+b(x+a) = (x+a)(x+b)